What is the wavelength λ of the photon that has been released in Part B?
ΔE = −2.04×10−18 J The energy of the photon emitted by the electron is
related to its wavelength by E=hcλ where λ is the wavelength in meters,
6.626×10−34 J⋅s is Planck’s constant, and 3.00×108 m/s is the speed of
light in a vacuum.
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